Giải bài tập 2 trang 177 sgk toán 4

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Bài 2: Trang 177 - sgk toán lớp 4

Tính:

a) + \(\frac{3}{10}\) - \(\frac{1}{2}\) ;

b) + \(\frac{8}{33}\) x \(\frac{3}{4}\) ;

c) x \(\frac{3}{14}\) : \(\frac{5}{8}\) ;

d) - \(\frac{7}{32}\) : \(\frac{21}{16}\) ;

Bài làm:

Bài 2:

a)

+ \(\frac{3}{10}\) - \(\frac{1}{2}\) = \(\frac{4}{10}\) + \(\frac{3}{10}\) - \(\frac{5}{10}\) = \(\frac{7}{10}\) - \(\frac{5}{10}\) = \(\frac{2}{10}\) = \(\frac{1}{5}\)

b)

+ \(\frac{8}{33}\) x \(\frac{3}{4}\) = + \(\frac{2}{11}\) = \(\frac{10}{11}\)

c)

x \(\frac{3}{14}\) : \(\frac{5}{8}\) = \(\frac{1}{6}\) : \(\frac{5}{8}\) = \(\frac{1}{6}\) x \(\frac{8}{5}\) = \(\frac{8}{30}\) = \(\frac{4}{15}\)

d)

- \(\frac{7}{32}\) : \(\frac{21}{16}\) = - \(\frac{7}{32}\) x \(\frac{16}{21}\) = - \(\frac{1}{6}\) = - \(\frac{2}{12}\) = \(\frac{3}{12}\)

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Cập nhật: 07/09/2021